How to automate comparison of md5sum hash values for a large number of files

For example I have a file called test_binary.

MD5 sum of file test is ef7ab26f9a3b2cbd35aa3e7e69aad86c

To test it automatically run this:

$ md5sum -c <<<"ef7ab26f9a3b2cbd35aa3e7e69aad86c *path/to/file/test_binary"
test_binary: OK

or

$ echo "595f44fec1e92a71d3e9e77456ba80d1  filetohashA.txt" | md5sum -c -

Quote from man

   -c, --check
          read MD5 sums from the FILEs and check them

Quote from wiki

Note: There must be two spaces between each md5sum value and filename to be compared. Otherwise, the following error will result: "no properly formatted MD5 checksum lines found".

Link to wiki

Also you can just read md5 hashes from file

$ md5sum -c md5sum_formatted_file.txt

It is expecting file with format:

<md5sum_checksum><space><space><file_name>

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About * and <space> after MD5 sum hash. There is little note in man:

 When  checking,  the
       input  should  be a former output of this program.  The default mode is
       to print a line with checksum, a character indicating input  mode  ('*'
       for binary, space for text), and name for each FILE.

And here is link to stackoverflow where I found answer on question, why should we, sometimes, distinguish binary files and text files.

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One possibility is to use the utility cfv

sudo apt-get install cfv

CFV supports many types of hashes, and both testing and hash file creation.

# List the files
$ ls
test.c
# Create a hash file
$ cfv -tmd5 -C
temp.md5: 1 files, 1 OK.  0.001 seconds, 302.7K/s
# Test the hash file
$ cfv -tmd5 -T
temp.md5: 1 files, 1 OK.  0.001 seconds, 345.1K/s
# Display the hash file
$ cat *.md5
636564b0b10b153219d6e0dfa917d1e3 *test.c