How to capitalize the first character of sentence using Swift
In Swift 2, you can do
String(text.characters.first!).capitalizedString + String(text.characters.dropFirst())
Another possibility in Swift 3:
extension String {
func capitalizeFirst() -> String {
let firstIndex = self.index(startIndex, offsetBy: 1)
return self.substring(to: firstIndex).capitalized + self.substring(from: firstIndex).lowercased()
}
}
For Swift 4:
Warnings from above Swift 3 code:
'substring(to:)' is deprecated: Please use String slicing subscript
with a 'partial range upto' operator.
'substring(from:)' is deprecated: Please use String slicing subscript with a 'partial range from' operator.
Swift 4 solution:
extension String {
var capitalizedFirst: String {
guard !isEmpty else {
return self
}
let capitalizedFirstLetter = charAt(i: 0).uppercased()
let secondIndex = index(after: startIndex)
let remainingString = self[secondIndex..<endIndex]
let capitalizedString = "\(capitalizedFirstLetter)\(remainingString)"
return capitalizedString
}
}
import Foundation
// A lowercase string
let description = "the quick brown fox jumps over the lazy dog."
// The start index is the first letter
let first = description.startIndex
// The rest of the string goes from the position after the first letter
// to the end.
let rest = advance(first,1)..<description.endIndex
// Glue these two ranges together, with the first uppercased, and you'll
// get the result you want. Note that I'm using description[first...first]
// to get the first letter because I want a String, not a Character, which
// is what you'd get with description[first].
let capitalised = description[first...first].uppercaseString + description[rest]
// Result: "The quick brown fox jumps over the lazy dog."
You may want to make sure there's at least one character in your sentence before you start, as otherwise you'll get a runtime error trying to advance the index beyond the end of the string.