How to cast an Object to an int
Scenario 1: simple case
If it's guaranteed that your object is an Integer
, this is the simple way:
int x = (Integer)yourObject;
Scenario 2: any numerical object
In Java Integer
, Long
, BigInteger
etc. all implement the Number
interface which has a method named intValue
. Any other custom types with a numerical aspect should also implement Number
(for example: Age implements Number
). So you can:
int x = ((Number)yourObject).intValue();
Scenario 3: parse numerical text
When you accept user input from command line (or text field etc.) you get it as a String
. In this case you can use Integer.parseInt(String string)
:
String input = someBuffer.readLine();
int x = Integer.parseInt(input);
If you get input as Object
, you can use (String)input
, or, if it can have an other textual type, input.toString()
:
int x = Integer.parseInt(input.toString());
Scenario 4: identity hash
In Java there are no pointers. However Object
has a pointer-like default implementation for hashCode()
, which is directly available via System.identityHashCode(Object o)
. So you can:
int x = System.identityHashCode(yourObject);
Note that this is not a real pointer value. Objects' memory address can be changed by the JVM while their identity hashes are keeping. Also, two living objects can have the same identity hash.
You can also use object.hashCode()
, but it can be type specific.
Scenario 5: unique index
In same cases you need a unique index for each object, like to auto incremented ID values in a database table (and unlike to identity hash which is not unique). A simple sample implementation for this:
class ObjectIndexer {
private int index = 0;
private Map<Object, Integer> map = new WeakHashMap<>();
// or:
// new WeakIdentityHashMap<>();
public int indexFor(Object object) {
if (map.containsKey(object)) {
return map.get(object);
} else {
index++;
map.put(object, index);
return index;
}
}
}
Usage:
ObjectIndexer indexer = new ObjectIndexer();
int x = indexer.indexFor(yourObject); // 1
int y = indexer.indexFor(new Object()); // 2
int z = indexer.indexFor(yourObject); // 1
Scenario 6: enum member
In Java enum members aren't integers but full featured objects (unlike C/C++, for example). Probably there is never a need to convert an enum object to int
, however Java automatically associates an index number to each enum member. This index can be accessed via Enum.ordinal()
, for example:
enum Foo { BAR, BAZ, QUX }
// ...
Object baz = Foo.BAZ;
int index = ((Enum)baz).ordinal(); // 1
Assuming the object is an Integer
object, then you can do this:
int i = ((Integer) obj).intValue();
If the object isn't an Integer
object, then you have to detect the type and convert it based on its type.
If you're sure that this object is an Integer
:
int i = (Integer) object;
Or, starting from Java 7, you can equivalently write:
int i = (int) object;
Beware, it can throw a ClassCastException
if your object isn't an Integer
and a NullPointerException
if your object is null
.
This way you assume that your Object is an Integer (the wrapped int) and you unbox it into an int.
int
is a primitive so it can't be stored as an Object
, the only way is to have an int
considered/boxed as an Integer
then stored as an Object
.
If your object is a String
, then you can use the Integer.valueOf()
method to convert it into a simple int :
int i = Integer.valueOf((String) object);
It can throw a NumberFormatException
if your object isn't really a String
with an integer as content.
Resources :
- Oracle.com - Autoboxing
- Oracle.com - Primitive Data types
On the same topic :
- Java: What's the difference between autoboxing and casting?
- Autoboxing: So I can write: Integer i = 0; instead of: Integer i = new Integer(0);
- Convert Object into primitive int