how to catch arithmetic exception java code example

Example 1: arithmetic exception in java

class Example1
{
   public static void main(String args[])
   {
      try{
         int num1=30, num2=0;
         int output=num1/num2;
         System.out.println ("Result: "+output);
      }
      catch(ArithmeticException e){
         System.out.println ("You Shouldn't divide a number by zero");
      }
   }
}

Example 2: try block in java

try {
  //  Block of code to try
}
catch(Exception e) {
  //  Block of code to handle errors
}

Example 3: try catch java

public class MyClass {
  public static void main(String[ ] args) {
    try {
      int[] myNumbers = {1, 2, 3, 4, 5, 6};
      System.out.println(myNumbers[10]);
    } catch (Exception e) {
      System.out.println("Something went wrong. check again");
    }
  }
}