How to check if 3 sides form a triangle in C++

Let's say that a, b, c is the sides of the triangle. Therefore, it must be satisfy this criteria :

1. a + b > c
2. a + c > b
3. b + c > a

All the criteria must be true. If one of them are false, then a, b, c will not create the triangle.

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
    int a, b, c;
    cin >> a >> b >> c;
    // check whether a, b, c can form a triangle
    if (a+b > c && a+c > b && b+c > a)
        cout << "The sides form a triangle" << endl;
    else
        cout << "The sides do not form a triangle." << endl;
    return 0;
}

Triangle conditions to check for,

(a + b > c),
(b + c > a),
(c + a > b)

For a normal triangle

1. sum of any two sides is greater than third side (or)
2. difference of any two sides is less than third side

hint :  a+b > c || ...

For a right angled triangle

1) sum of the squares of two sides equals the square of the longest side

Hint:

Find the longest side of three sides, that is find longest number in the three..
square the remaining two nums, add them and equate it to square of longest number