How to check if an object is nullable?

There are two types of nullable - Nullable<T> and reference-type.

Jon has corrected me that it is hard to get type if boxed, but you can with generics: - so how about below. This is actually testing type T, but using the obj parameter purely for generic type inference (to make it easy to call) - it would work almost identically without the obj param, though.

static bool IsNullable<T>(T obj)
{
    if (obj == null) return true; // obvious
    Type type = typeof(T);
    if (!type.IsValueType) return true; // ref-type
    if (Nullable.GetUnderlyingType(type) != null) return true; // Nullable<T>
    return false; // value-type
}

But this won't work so well if you have already boxed the value to an object variable.

Microsoft documentation: https://docs.microsoft.com/en-us/dotnet/csharp/programming-guide/nullable-types/how-to-identify-a-nullable-type


There is a very simple solution using method overloads

http://deanchalk.com/is-it-nullable/

excerpt:

public static class ValueTypeHelper
{
    public static bool IsNullable<T>(T t) { return false; }
    public static bool IsNullable<T>(T? t) where T : struct { return true; }
}

then

static void Main(string[] args)
{
    int a = 123;
    int? b = null;
    object c = new object();
    object d = null;
    int? e = 456;
    var f = (int?)789;
    bool result1 = ValueTypeHelper.IsNullable(a); // false
    bool result2 = ValueTypeHelper.IsNullable(b); // true
    bool result3 = ValueTypeHelper.IsNullable(c); // false
    bool result4 = ValueTypeHelper.IsNullable(d); // false
    bool result5 = ValueTypeHelper.IsNullable(e); // true
    bool result6 = ValueTypeHelper.IsNullable(f); // true

This works for me and seems simple:

static bool IsNullable<T>(T obj)
{
    return default(T) == null;
}

For value types:

static bool IsNullableValueType<T>(T obj)
{
    return default(T) == null && typeof(T).BaseType != null && "ValueType".Equals(typeof(T).BaseType.Name);
}

Tags:

C#

.Net

Nullable