how to check if number is in array java code example

Example 1: Check if an array contains an element java

import java.util.Arrays;

// For String
String[] array = {"Boto", "Nesto", "Lepta"};
String toSearch = "Nesto";

// Inline
if (Arrays.toString(array).contains(toSearch)) {
	// Do something if it's found
}

// Multi line
String strArray = Array.toString(array);
if (strArray.contains(toSearch)) {
	// Do your thing
}

// Different elements
int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
int number = 5;

String checker = Arrays.toString(numbers);

// The toString of int in some cases can happen without explicitly saying so
// In this example we convert both
if (checker.contains(Integer.toString(number)) {
	// Found.     
}

Example 2: java check if element exists in array

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}
Copy

Example 3: java check if element exists in array

// Convert to stream and test it
	boolean result = Arrays.stream(alphabet).anyMatch("A"::equals);
	if (result) {
		System.out.println("Hello A");
	}
Copy