How to check whether my OS is 64-bit or 32-bit?
If you were to do any actions using CMD scripting in Windows, you could start the batch file something like this:
@echo off
if %PROCESSOR_ARCHITECTURE% == x86 (
goto :x86
) else (
goto :x64
)
:x86
start "foo.exe"
goto :eof
:x64
start "bar.exe"
goto :eof
In many Unix-like systems you can type in:
uname -a
For FreeBSD it looks like:
FreeBSD whiplash 8.0-STABLE FreeBSD 8.0-STABLE #1:
Tue Mar 9 15:38:19 CET 2010 root@beast:/usr/obj/usr/src/sys/WHIPLASH amd64
(amd64 means that this kernel is 64-bit)
For Linux:
Linux softy.vm 2.6.18-128.el5 #1 SMP
Wed Jan 21 10:44:23 EST 2009 i686 athlon i386 GNU/Linux
(i386 means that this kernel is 32-bit)
For MacOSX:
Darwin iMac.local 10.0.0 Darwin Kernel Version 10.0.0: Fri Jul 31 22:47:34 PDT 2009;
root:xnu 1456.1.25~1/RELEASE_X86_64 x86_64
(x86_64 means that this kernel is 64-bit)
Under Windows:
The GUI Way
- Press Win+R to open the Run... Dialog
- Enter winmsd
- Look for row Processor or System type
If they begin with x86 you have 32-Bit otherwise you have 64-Bit
Using cmd.exe
Enter SET PROCESSOR_ARCHITECTURE
x86 means 32-Bit, otherwise it's 64-Bit
Using Powershell
Enter $env:PROCESSOR_ARCHITECTURE
Meaning is the same as with using cmd.exe
Beware
There are two different types of 64-Bit architectures.
One is AMD64 for x64 the other is ia64 for Itanium (not sure this value is exactly like that, never worked with any of them)