How to compare two dates?
Use time
Let's say you have the initial dates as strings like these:
date1 = "31/12/2015"
date2 = "01/01/2016"
You can do the following:
newdate1 = time.strptime(date1, "%d/%m/%Y")
newdate2 = time.strptime(date2, "%d/%m/%Y")
to convert them to python's date format. Then, the comparison is obvious:
newdate1 > newdate2
will returnFalse
newdate1 < newdate2
will returnTrue
Use the datetime
method and the operator <
and its kin.
>>> from datetime import datetime, timedelta
>>> past = datetime.now() - timedelta(days=1)
>>> present = datetime.now()
>>> past < present
True
>>> datetime(3000, 1, 1) < present
False
>>> present - datetime(2000, 4, 4)
datetime.timedelta(4242, 75703, 762105)
datetime.date(2011, 1, 1) < datetime.date(2011, 1, 2)
will return True
.
datetime.date(2011, 1, 1) - datetime.date(2011, 1, 2)
will return datetime.timedelta(-1)
.
datetime.date(2011, 1, 1) + datetime.date(2011, 1, 2)
will return datetime.timedelta(1)
.
see the docs.
Other answers using datetime
and comparisons also work for time only, without a date.
For example, to check if right now it is more or less than 8:00 a.m., we can use:
import datetime
eight_am = datetime.time( 8,0,0 ) # Time, without a date
And later compare with:
datetime.datetime.now().time() > eight_am
which will return True