How to concatenate two IEnumerable<T> into a new IEnumerable<T>?
Yes, LINQ to Objects supports this with Enumerable.Concat
:
var together = first.Concat(second);
NB: Should first
or second
be null you would receive a ArgumentNullException
. To avoid this & treat nulls as you would an empty set, use the null coalescing operator like so:
var together = (first ?? Enumerable.Empty<string>()).Concat(second ?? Enumerable.Empty<string>()); //amending `<string>` to the appropriate type
The Concat
method will return an object which implements IEnumerable<T>
by returning an object (call it Cat) whose enumerator will attempt to use the two passed-in enumerable items (call them A and B) in sequence. If the passed-in enumerables represent sequences which will not change during the lifetime of Cat, and which can be read from without side-effects, then Cat may be used directly. Otherwise, it may be a good idea to call ToList()
on Cat
and use the resulting List<T>
(which will represent a snapshot of the contents of A and B).
Some enumerables take a snapshot when enumeration begins, and will return data from that snapshot if the collection is modified during enumeration. If B is such an enumerable, then any change to B which occurs before Cat has reached the end of A will show up in Cat's enumeration, but changes which occur after that will not. Such semantics may likely be confusing; taking a snapshot of Cat can avoid such issues.
You can use below code for your solution:-
public void Linq94()
{
int[] numbersA = { 0, 2, 4, 5, 6, 8, 9 };
int[] numbersB = { 1, 3, 5, 7, 8 };
var allNumbers = numbersA.Concat(numbersB);
Console.WriteLine("All numbers from both arrays:");
foreach (var n in allNumbers)
{
Console.WriteLine(n);
}
}