How to convert an Int to a Character in Swift

How to convert an Int to a Character in Swift

For the sake of future visitors, I am providing a basic answer to the question title rather than the details of the question itself.

It is a two step process. Convert the Int to a UnicodeScalar and then convert the UnicodeScalar to a Character.

let myInteger: Int = 97

// convert Int to a valid UnicodeScalar
guard let myUnicodeScalar = UnicodeScalar(myInteger) else {
    return
}

// convert UnicodeScalar to Character
let myCharacter = Character(myUnicodeScalar)

// results
print(myCharacter) // a

(source)

Or alternatively...

if let myUnicodeScalar = UnicodeScalar(97) 
    let myCharacter = Character(myUnicodeScalar)
}

See also

• How to express Strings in Swift using Unicode hexadecimal values (UTF-16)
• Working with Unicode code points in Swift

try this

for i in 0...25
{
    let string = String(format: "%c", i+65) as String
    NSLog("%@", string)
}

You can't convert an integer directly to a Character instance, but you can go from integer to UnicodeScalar to Character and back again:

let startingValue = Int(("A" as UnicodeScalar).value) // 65
for i in 0 ..< 26 {
    print(Character(UnicodeScalar(i + startingValue)))
}