How to convert float to int with Java

Using Math.round() will round the float to the nearest integer.

Math.round also returns an integer value, so you don't need to typecast.

int b = Math.round(float a);

Math.round(value) round the value to the nearest whole number.

Use

1) b=(int)(Math.round(a));

2) a=Math.round(a);  
   b=(int)a;

Actually, there are different ways to downcast float to int, depending on the result you want to achieve: (for int i, float f)

• round (the closest integer to given float)

  i = Math.round(f);
    f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  3
    f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -3
  

  note: this is, by contract, equal to (int) Math.floor(f + 0.5f)

• truncate (i.e. drop everything after the decimal dot)

  i = (int) f;
    f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
    f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
  

• ceil/floor (an integer always bigger/smaller than a given value if it has any fractional part)

  i = (int) Math.ceil(f);
    f =  2.0 -> i =  2 ; f =  2.22 -> i =  3 ; f =  2.68 -> i =  3
    f = -2.0 -> i = -2 ; f = -2.22 -> i = -2 ; f = -2.68 -> i = -2
  
  i = (int) Math.floor(f);
    f =  2.0 -> i =  2 ; f =  2.22 -> i =  2 ; f =  2.68 -> i =  2
    f = -2.0 -> i = -2 ; f = -2.22 -> i = -3 ; f = -2.68 -> i = -3
  

For rounding positive values, you can also just use (int)(f + 0.5), which works exactly as Math.Round in those cases (as per doc).

You can also use Math.rint(f) to do the rounding to the nearest even integer; it's arguably useful if you expect to deal with a lot of floats with fractional part strictly equal to .5 (note the possible IEEE rounding issues), and want to keep the average of the set in place; you'll introduce another bias, where even numbers will be more common than odd, though.

See

http://mindprod.com/jgloss/round.html

http://docs.oracle.com/javase/6/docs/api/java/lang/Math.html

for more information and some examples.