how to create array of an abstract class in c++

You cannot create instances of abstract classes, but you can assign concrete derived instances to pointers or references of the base class.

int main()
{
  Dessert d("brownie");
  Pizza p("BBQ delux");
  Food* array[2] = {&d,&p};
}

then work with array

array[0]->print_food();

You need reference semantics for that, because Food arr[2]; tries to initialize the array with default values (which are abstract, thus not constructible).

I think std::array<std::unique_ptr<Food>, 2> arr; should be the most natural to use in this case.

std::array<std::unique_ptr<Food>> arr = {
    std::make_unique<Dessert>("brownie"),
    std::make_unique<Pizza>("BBQ delux")
};

If you just want to loop over those two values, though, using initializer_list would be easiest, I suppose.

for (auto f : std::initializer_list<Food*>{&d,&p})
    f->commonMemberFunction();

Unfortunately it won't deduce the correct type from just {}, but a helper could be created, I suppose,

Starting with C++11, you can use std::reference_wrapper too. It's very similar to @Mykola's answer, but uses references:

#include <functional>  // for std::reference_wrapper

int main()
{
  Dessert d("brownie");
  Pizza p("BBQ delux");
  std::reference_wrapper<Food> array = {d, p};

  // just to see they're references, they have same memory addresses as
  // the initial variables.
  for (const Food &f : array) {
    std::cout << &f << " ";
  }
  std::cout << "\n" << &d << " " << &p << "\n";
}

Unfortunately the same restriction applies to this and to the version with pointers. You need to have local variables defined, you can't just use anonymous objects here.

This won't work:

  std::reference_wrapper<Food> array = {Dessert("brownie"), Pizza("BBQ delux")};