How to delete multiple files at once in Bash on Linux?

If you want to delete all files whose names match a particular form, a wildcard (glob pattern) is the most straightforward solution. Some examples:

$ rm -f abc.log.*             # Remove them all
$ rm -f abc.log.2012*         # Remove all logs from 2012
$ rm -f abc.log.2012-0[123]*  # Remove all files from the first quarter of 2012

Regular expressions are more powerful than wildcards; you can feed the output of grep to rm -f. For example, if some of the file names start with "abc.log" and some with "ABC.log", grep lets you do a case-insensitive match:

$ rm -f $(ls | grep -i '^abc\.log\.')

This will cause problems if any of the file names contain funny characters, including spaces. Be careful.

When I do this, I run the ls | grep ... command first and check that it produces the output I want -- especially if I'm using rm -f:

$ ls | grep -i '^abc\.log\.'
(check that the list is correct)
$ rm -f $(!!)

where !! expands to the previous command. Or I can type up-arrow or Ctrl-P and edit the previous line to add the rm -f command.

This assumes you're using the bash shell. Some other shells, particularly csh and tcsh and some older sh-derived shells, may not support the $(...) syntax. You can use the equivalent backtick syntax:

$ rm -f `ls | grep -i '^abc\.log\.'`

The $(...) syntax is easier to read, and if you're really ambitious it can be nested.

Finally, if the subset of files you want to delete can't be easily expressed with a regular expression, a trick I often use is to list the files to a temporary text file, then edit it:

$ ls > list
$ vi list   # Use your favorite text editor

I can then edit the list file manually, leaving only the files I want to remove, and then:

$ rm -f $(<list)

or

$ rm -f `cat list`

(Again, this assumes none of the file names contain funny characters, particularly spaces.)

Or, when editing the list file, I can add rm -f to the beginning of each line and then:

$ . ./list

or

$ source ./list

Editing the file is also an opportunity to add quotes where necessary, for example changing rm -f foo bar to rm -f 'foo bar' .

Just use multiline selection in sublime to combine all of the files into a single line and add a space between each file name and then add rm at the beginning of the list. This is mostly useful when there isn't a pattern in the filenames you want to delete.

[$]> rm abc.log.2012-03-14 abc.log.2012-03-27 abc.log.2012-03-28 abc.log.2012-03-29 abc.log.2012-03-30 abc.log.2012-04-02 abc.log.2012-04-04 abc.log.2012-04-05 abc.log.2012-04-09 abc.log.2012-04-10

Bash supports all sorts of wildcards and expansions.

Your exact case would be handled by brace expansion, like so:

$ rm -rf abc.log.2012-03-{14,27,28}

The above would expand to a single command with all three arguments, and be equivalent to typing:

$ rm -rf abc.log.2012-03-14 abc.log.2012-03-27 abc.log.2012-03-28

It's important to note that this expansion is done by the shell, before rm is even loaded.

Use a wildcard (*) to match multiple files.

For example, the command below will delete all files with names beginning with abc.log.2012-03-.

rm -f abc.log.2012-03-*

I'd recommend running ls abc.log.2012-03-* to list the files so that you can see what you are going to delete before running the rm command.

For more details see the Bash man page on filename expansion.