How to detect the OS from a Bash script?
I think the following should work. I'm not sure about win32
though.
if [[ "$OSTYPE" == "linux-gnu"* ]]; then
# ...
elif [[ "$OSTYPE" == "darwin"* ]]; then
# Mac OSX
elif [[ "$OSTYPE" == "cygwin" ]]; then
# POSIX compatibility layer and Linux environment emulation for Windows
elif [[ "$OSTYPE" == "msys" ]]; then
# Lightweight shell and GNU utilities compiled for Windows (part of MinGW)
elif [[ "$OSTYPE" == "win32" ]]; then
# I'm not sure this can happen.
elif [[ "$OSTYPE" == "freebsd"* ]]; then
# ...
else
# Unknown.
fi
For my .bashrc, I use the following code:
platform='unknown'
unamestr=`uname`
if [[ "$unamestr" == 'Linux' ]]; then
platform='linux'
elif [[ "$unamestr" == 'FreeBSD' ]]; then
platform='freebsd'
fi
Then I do somethings like:
if [[ $platform == 'linux' ]]; then
alias ls='ls --color=auto'
elif [[ $platform == 'freebsd' ]]; then
alias ls='ls -G'
fi
It's ugly, but it works. You may use case
instead of if
if you prefer.
The bash manpage says that the variable OSTYPE stores the name of the operation system:
OSTYPE
Automatically set to a string that describes the operating system on which bash is executing. The default is system- dependent.
It is set to linux-gnu
here. jio