How to do a count on a union query
This will perform pretty well:
select count(*) from (
select profile_id
from userprofile_...
union
select profile_id
from productions_...
) x
The use of union
guarantees distinct values - union
removes duplicates, union all
preserves them. This means you don't need the distinct
keyword (the other answers don't exploit this fact and end up doing more work).
Edited:
If you want to total number of different profile_id in each, where given values that appear in both table are considered different values, use this:
select sum(count) from (
select count(distinct profile_id) as count
from userprofile_...
union all
select count(distinct profile_id)
from productions_...
) x
This query will out-perform all other answers, because the database can efficiently count distinct values within a table much faster than from the unioned list. The sum()
simply adds the two counts together.
If you want a total count for all records, then you would do this:
SELECT COUNT(*)
FROM
(
select distinct profile_id
from userprofile_...
union all
select distinct profile_id
from productions_...
) x
you should use Union All
if there are equals rows in both tables, because Union makes a distinct
select count(*) from
(select distinct profile_id from userprofile_...
union ALL
select distinct profile_id from productions_...) x
In this case, if you got a same Profile_Id
in both tables (id is probably a number, so it's possible), then if you use Union
, if you got Id = 1
in both tables
, you will lose one row (it will appear one time instead of two)