How to do a non-greedy match in grep?

My grep that works after trying out stuff in this thread:

echo "hi how are you " | grep -shoP ".*? "

Just make sure you append a space to each one of your lines

(Mine was a line by line search to spit out words)

You're looking for a non-greedy (or lazy) match. To get a non-greedy match in regular expressions you need to use the modifier ? after the quantifier. For example you can change .* to .*?.

By default grep doesn't support non-greedy modifiers, but you can use grep -P to use the Perl syntax.

Actualy the .*? only works in perl. I am not sure what the equivalent grep extended regexp syntax would be. Fortunately you can use perl syntax with grep so grep -P would work but grep -E which is same as egrep would not work (it would be greedy).

See also: http://blog.vinceliu.com/2008/02/non-greedy-regular-expression-matching.html