How to escape parenthesis in grep
If you want to search for exactly the string "init()" then use fgrep "init()"
or grep -F "init()"
.
Both of these will do fixed string matching, i.e. will treat the pattern as a plain string to search for and not as a regex. I believe it is also faster than doing a regex search.
It depends. If you use regular grep, you don't escape:
echo '(foo)' | grep '(fo*)'
You actually have to escape if you want to use the parentheses as grouping.
If you use extended regular expressions, you do escape:
echo '(foo)' | grep -E '\(fo*\)'
Move to your root directory (if you are aware where the JavaScript files are). Then do the following.
grep 'init()' *.js
$ echo "init()" | grep -Erin 'init\([^)]*\)'
1:init()
$ echo "init(test)" | grep -Erin 'init\([^)]*\)'
1:init(test)
$ echo "initwhat" | grep -Erin 'init\([^)]*\)'