How to execute consecutive commands from history?

If it refers to commands run just recently, a more efficient way is to reference them with negative numbers:

!-4; !-3; !-2; !-1

Also, once you do it, your last history entry will contain the whole chain of commands, so you can repeat it with !!.

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Edit: If you haven't already, get familiar with the great builtin function fc, mentioned by Gilles. (Use help fc.) It turns out that you can also use negative numbers with it, so you could do the same as above using

eval "`fc -ln -4 -1`"

This has one caveat, though: after this, the eval line is stored in the history as the last command. So if you run this again, you'll fall into a loop!

A safer way of doing this is to use the default fc operation mode: forwarding the selected range of commands to an editor and running them once you exit from it. Try:

 fc -4 -1

You can even reverse the order of the range of commands: fc -1 -4

To view a range of commands in the history use the built-in fc command:

fc -ln 432 435

To execute them again:

eval "$(fc -ln 432 435)"

To execute the commands immediately rather than edit them, here is a syntactically slimmer version of Giles answer using eval:

fc -e: 432 435

The colon argument to -e is the bash noop, which has the effect of skipping the "open in an editor" step that fc wants. Also, now the (recent) history will contain the actual commands from history, rather than the eval statement.