How to expand a list to function arguments in Python

It exists, but it's hard to search for. I think most people call it the "splat" operator.

It's in the documentation as "Unpacking argument lists".

You'd use it like this for positional arguments:

values = [1, 2]
foo(*values)

There's also one for dictionaries to call with named arguments:

d = {'a': 1, 'b': 2}
def foo(a, b):
    pass
foo(**d)

You should use the * operator, like foo(*values) Read the Python doc unpackaging argument lists.

Also, do read this: http://www.saltycrane.com/blog/2008/01/how-to-use-args-and-kwargs-in-python/

def foo(x,y,z):
   return "%d, %d, %d" % (x,y,z)

values = [1,2,3]

# the solution.
foo(*values)

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