How to find length of dictionary values
Sure. In this case, you'd just do:
length_key = len(d['key']) # length of the list stored at `'key'` ...
It's hard to say why you actually want this, but, perhaps it would be useful to create another dict that maps the keys to the length of values:
length_dict = {key: len(value) for key, value in d.items()}
length_key = length_dict['key'] # length of the list stored at `'key'` ...
To find all of the lengths of the values in a dictionary you can do this:
lengths = [len(v) for v in d.values()]
A common use case I have is a dictionary of numpy arrays or lists where I know they're all the same length, and I just need to know one of them (e.g. I'm plotting timeseries data and each timeseries has the same number of timesteps). I often use this:
length = len(next(iter(d.values())))
Lets do some experimentation, to see how we could get/interpret the length of different dict/array values in a dict.
create our test dict, see list and dict comprehensions:
>>> my_dict = {x:[i for i in range(x)] for x in range(4)}
>>> my_dict
{0: [], 1: [0], 2: [0, 1], 3: [0, 1, 2]}
Get the length of the value of a specific key:
>>> my_dict[3]
[0, 1, 2]
>>> len(my_dict[3])
3
Get a dict of the lengths of the values of each key:
>>> key_to_value_lengths = {k:len(v) for k, v in my_dict.items()}
{0: 0, 1: 1, 2: 2, 3: 3}
>>> key_to_value_lengths[2]
2
Get the sum of the lengths of all values in the dict:
>>> [len(x) for x in my_dict.values()]
[0, 1, 2, 3]
>>> sum([len(x) for x in my_dict.values()])
6