how to find the min of an array in java code example
Example 1: find min in array java
private static int findMin(int[] array) {
int min = array[0];
for(int i=1;i<array.length;i++) {
if(min > array[i]) {
min = array[i];
}
}
return min;
}
Example 2: how to get the max value of an array java
import java.util.Random;
public class Main {
public static void main(String[] args) {
int a[] = new int [100];
Random rnd = new Random ();
for (int i = 0; i< a.length; i++) {
a[i] = rnd.nextInt(99-0)+0;
System.out.println(a[i]);
}
int max = 0;
for (int i = 0; i < a.length; i++) {
a[i] = max;
for (int j = i+1; j<a.length; j++) {
if (a[j] > max) {
max = a[j];
}
}
}
System.out.println("Max element: " + max);
}
}
Example 3: java 8 find min value in array
package com.concerned.crossbill;
import java.util.Arrays;
public class Foo {
public int getMin(int[] numbers) {
return Arrays.stream(numbers).min().getAsInt();
}
}
import org.junit.Test;
import static org.junit.Assert.assertEquals;
import com.concerned.crossbill.Foo;
public class FooTest {
public void testGetMin() {
int[] numbers = new int[]{12, 10, 31, 30, 23, 4, 5, 5, 5, 5, 10, 40};
Foo foo = new Foo();
int result = foo.getMin(numbers);
int expResult = 4;
assertEquals(expResult, result);
}
}
Example 4: finding min and max from given number in java
Scanner input = new Scanner(System.in);
int count = 0;
int min = 0;
int max = 0;
boolean bugSolved = true;
while (true){
int cnt = count++;
System.out.print("Enter Number #"+(cnt+1)+": ");
boolean isValid = input.hasNextInt();
if(isValid){
int num = input.nextInt();
if (num < min) {
min = num;
}else if (num > max){
max = num;
}
}else{
System.out.println("Invalid input..");
break;
}
input.nextLine();
}
System.out.println("Min Number : " + min);
System.out.println("Max Number : " + max);