How to force watch to run under bash

The default shell for watch is /bin/sh. Shells will not inherit exported variables or functions from other types of shell.

If your system does not symlink /bin/sh to /bin/bash (or your current shell) then you can instruct watch to exec your shell by using -x or --exec:

watch -x bash -c "my_func"

or

watch --exec bash -c "my_func"

This is different to watch bash -c "test_watch" (excluding the --exec) as it doesn't use /bin/sh to spawn the child process (in this case, bash), maintaining bash all the way down. As caveated in other answers, this can get messy if exporting functions that are highly coupled to the current environment (i.e. requiring other variables or functions).

---

An example:

test_watch() { echo 'Working!'; }
export -f test_watch
watch --exec bash -c "test_watch"

gives the familiar

Every 2.0s: bash -c test_watch                                   Thu Mar 31 11:15:56 2016

Working!

Ok, so there are a few issues with your approach.

You are exporting a function, which is not portable between shells. watch executes its commands with /bin/sh, which on your system is not bash. And whatever shell it is, it doesn't respect function exports, so you get the error.

Secondly, you can change your command to something like watch bash -c 'func1', but this may not work well either.
The reason here being that any variables set by the script won't be available to the function. You might be able to export the ones it needs, but that starts getting messy.

The safest solution is to put func1 in a script by itself and call that script.
 

In short, try:

watch bash -c func1

Why run watch from inside your script? Why not have this shell script:

$ cat func1 
#!/bin/bash

func1(){
  echo $1
}

func1 $1

... and then run it like so ...

$ watch func1 foo