How to get google search results
I created this function to read in a list of company names and then get the top website result for each. It will get you started then you can adjust it as needed.
#libraries.
library(URLencode)
library(rvest)
#load data
d <-read.csv("P:\\needWebsites.csv")
c <- as.character(d$Company.Name)
# Function for getting website.
getWebsite <- function(name)
{
url = URLencode(paste0("https://www.google.com/search?q=",name))
page <- read_html(url)
results <- page %>%
html_nodes("cite") %>% # Get all notes of type cite. You can change this to grab other node types.
html_text()
result <- results[1]
return(as.character(result)) # Return results if you want to see them all.
}
# Apply the function to a list of company names.
websites <- data.frame(Website = sapply(c,getWebsite))]
If you look at the html
variable, you can see that the search result links all are nested in <h3 class="r">
tags.
Try to change your getGoogleLinks
function to:
getGoogleLinks <- function(google.url) {
doc <- getURL(google.url, httpheader = c("User-Agent" = "R
(2.10.0)"))
html <- htmlTreeParse(doc, useInternalNodes = TRUE, error=function
(...){})
nodes <- getNodeSet(html, "//h3[@class='r']//a")
return(sapply(nodes, function(x) x <- xmlAttrs(x)[["href"]]))
}
other solutions here don't work for me, here's my take on @Bryce-Chamberlain's issue which works for me in August 2019, it answers also another closed question : company name to URL in R
# install.packages("rvest")
get_first_google_link <- function(name, root = TRUE) {
url = URLencode(paste0("https://www.google.com/search?q=",name))
page <- xml2::read_html(url)
# extract all links
nodes <- rvest::html_nodes(page, "a")
links <- rvest::html_attr(nodes,"href")
# extract first link of the search results
link <- links[startsWith(links, "/url?q=")][1]
# clean it
link <- sub("^/url\\?q\\=(.*?)\\&sa.*$","\\1", link)
# get root if relevant
if(root) link <- sub("^(https?://.*?/).*$", "\\1", link)
link
}
companies <- data.frame(company = c("apple acres llc","abbvie inc","apple inc"))
companies <- transform(companies, url = sapply(company,get_first_google_link))
companies
#> company url
#> 1 apple acres llc https://www.appleacresllc.com/
#> 2 abbvie inc https://www.abbvie.com/
#> 3 apple inc https://www.apple.com/
Created on 2019-08-10 by the reprex package (v0.2.1)