How to get hex color value rather than RGB value?
Here is the cleaner solution I wrote based on @Matt suggestion:
function rgb2hex(rgb) {
rgb = rgb.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
function hex(x) {
return ("0" + parseInt(x).toString(16)).slice(-2);
}
return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);
}
Some browsers already returns colors as hexadecimal (as of Internet Explorer 8 and below). If you need to deal with those cases, just append a condition inside the function, like @gfrobenius suggested:
function rgb2hex(rgb) {
if (/^#[0-9A-F]{6}$/i.test(rgb)) return rgb;
rgb = rgb.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
function hex(x) {
return ("0" + parseInt(x).toString(16)).slice(-2);
}
return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);
}
If you're using jQuery and want a more complete approach, you can use CSS Hooks available since jQuery 1.4.3, as I showed when answering this question: Can I force jQuery.css("backgroundColor") returns on hexadecimal format?
var hexDigits = new Array
("0","1","2","3","4","5","6","7","8","9","a","b","c","d","e","f");
//Function to convert rgb color to hex format
function rgb2hex(rgb) {
rgb = rgb.match(/^rgb\((\d+),\s*(\d+),\s*(\d+)\)$/);
return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);
}
function hex(x) {
return isNaN(x) ? "00" : hexDigits[(x - x % 16) / 16] + hexDigits[x % 16];
}
(Source)
Most browsers seem to return the RGB value when using:
$('#selector').css('backgroundColor');
Only I.E (only 6 tested so far) returns the Hex value.
To avoid error messages in I.E, you could wrap the function in an if statement:
function rgb2hex(rgb) {
if ( rgb.search("rgb") == -1 ) {
return rgb;
} else {
rgb = rgb.match(/^rgba?\((\d+),\s*(\d+),\s*(\d+)(?:,\s*(\d+))?\)$/);
function hex(x) {
return ("0" + parseInt(x).toString(16)).slice(-2);
}
return "#" + hex(rgb[1]) + hex(rgb[2]) + hex(rgb[3]);
}
}