How to get the caller's method name in the called method?

inspect.getframeinfo and other related functions in inspect can help:

>>> import inspect
>>> def f1(): f2()
... 
>>> def f2():
...   curframe = inspect.currentframe()
...   calframe = inspect.getouterframes(curframe, 2)
...   print('caller name:', calframe[1][3])
... 
>>> f1()
caller name: f1

this introspection is intended to help debugging and development; it's not advisable to rely on it for production-functionality purposes.

Shorter version:

import inspect

def f1(): f2()

def f2():
    print 'caller name:', inspect.stack()[1][3]

f1()

(with thanks to @Alex, and Stefaan Lippen)

This seems to work just fine:

import sys
print sys._getframe().f_back.f_code.co_name