How to get the employees with their managers

(SELECT ename FROM EMP WHERE empno = mgr)

There are no records in EMP that meet this criteria.

You need to self-join to get this relation.

SELECT e.ename AS Employee, e.empno, m.ename AS Manager, m.empno
FROM EMP AS e LEFT OUTER JOIN EMP AS m
ON e.mgr =m.empno;

EDIT:

The answer you selected will not list your president because it's an inner join. I'm thinking you'll be back when you discover your output isn't what your (I suspect) homework assignment required. Here's the actual test case:

> select * from emp;

 empno | ename |    job    | deptno | mgr  
-------+-------+-----------+--------+------
  7839 | king  | president |     10 |     
  7698 | blake | manager   |     30 | 7839
(2 rows)

> SELECT e.ename employee, e.empno, m.ename manager, m.empno
FROM emp AS e LEFT OUTER JOIN emp AS m
ON e.mgr =m.empno;

 employee | empno | manager | empno 
----------+-------+---------+-------
 king     |  7839 |         |      
 blake    |  7698 | king    |  7839
(2 rows)

The difference is that an outer join returns all the rows. An inner join will produce the following:

> SELECT e.ename, e.empno, m.ename as manager, e.mgr
FROM emp e, emp m
WHERE e.mgr = m.empno;

 ename | empno | manager | mgr  
-------+-------+---------+------
 blake |  7698 | king    | 7839
(1 row)

This is a classic self-join, try the following:

SELECT e.ename, e.empno, m.ename as manager, e.mgr
FROM
    emp e, emp m
WHERE e.mgr = m.empno

And if you want to include the president which has no manager then instead of an inner join use an outer join in Oracle syntax:

SELECT e.ename, e.empno, m.ename as manager, e.mgr
FROM
    emp e, emp m
WHERE e.mgr = m.empno(+)

Or in ANSI SQL syntax:

SELECT e.ename, e.empno, m.ename as manager, e.mgr
FROM
    emp e
    LEFT OUTER JOIN emp m
        ON e.mgr = m.empno