How to get the last characters in a String in Java, regardless of String size

Lots of things you could do.

s.substring(s.lastIndexOf(':') + 1);

will get everything after the last colon.

s.substring(s.lastIndexOf(' ') + 1);

everything after the last space.

String numbers[] = s.split("[^0-9]+");

splits off all sequences of digits; the last element of the numbers array is probably what you want.

This question is the top Google result for "Java String Right".

Surprisingly, no-one has yet mentioned Apache Commons StringUtils.right():

String numbers = org.apache.commons.lang.StringUtils.right( text, 7 );

This also handles the case where text is null, where many of the other answers would throw a NullPointerException.

How about:

String numbers = text.substring(text.length() - 7);

That assumes that there are 7 characters at the end, of course. It will throw an exception if you pass it "12345". You could address that this way:

String numbers = text.substring(Math.max(0, text.length() - 7));

String numbers = text.length() <= 7 ? text : text.substring(text.length() - 7);

Note that this still isn't doing any validation that the resulting string contains numbers - and it will still throw an exception if text is null.

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