How to get the number of files in a folder as a variable?
ls -l | grep -v ^d | wc -l
One line.
How about:
count=$(find .. -maxdepth 1 -type f|wc -l)
echo $count
let count=count+1 # Increase by one, for the next file number
echo $count
Note that this solution is not efficient: it spawns sub shells for the find
and wc
commands, but it should work.
The quotes are causing the error messages.
To get a count of files in the directory:
shopt -s nullglob
numfiles=(*)
numfiles=${#numfiles[@]}
which creates an array and then replaces it with the count of its elements. This will include files and directories, but not dotfiles or .
or ..
or other dotted directories.
Use nullglob
so an empty directory gives a count of 0 instead of 1.
You can instead use find -type f
or you can count the directories and subtract:
# continuing from above
numdirs=(*/)
numdirs=${#numdirs[@]}
(( numfiles -= numdirs ))
Also see "How can I find the latest (newest, earliest, oldest) file in a directory?"
You can have as many spaces as you want inside an execution block. They often aid in readability. The only downside is that they make the file a little larger and may slow initial parsing (only) slightly. There are a few places that must have spaces (e.g. around [
, [[
, ]
, ]]
and =
in comparisons) and a few that must not (e.g. around =
in an assignment.