How to get the path of running java program

    ClassLoader cl = ClassLoader.getSystemClassLoader();

    URL[] urls = ((URLClassLoader)cl).getURLs();

    for(URL url: urls){
        System.out.println(url.getFile());
    }

Try this code:

final File f = new File(MyClass.class.getProtectionDomain().getCodeSource().getLocation().getPath());

replace 'MyClass' with your class containing the main method.

Alternatively you can also use

System.getProperty("java.class.path")

Above mentioned System property provides

Path used to find directories and JAR archives containing class files. Elements of the class path are separated by a platform-specific character specified in the path.separator property.

You actually do not want to get the path to your main class. According to your example you want to get the current working directory, i.e. directory where your program started. In this case you can just say new File(".").getAbsolutePath()

Use

System.getProperty("java.class.path")

see http://docs.oracle.com/javase/tutorial/essential/environment/sysprop.html

You can also split it into it's elements easily

String classpath = System.getProperty("java.class.path");
String[] classpathEntries = classpath.split(File.pathSeparator);