How to implement a pseudo blocking async queue in JS/TS?

It's quite simple actually, dequeue will create a promise that enqueue will resolve. We just have to keep the resolvers in a queue - and also care about the case where values are enqueued before they are dequeued, keeping the already fulfilled promises in a queue.

class AsyncBlockingQueue {
  constructor() {
    // invariant: at least one of the arrays is empty
    this.resolvers = [];
    this.promises = [];
  }
  _add() {
    this.promises.push(new Promise(resolve => {
      this.resolvers.push(resolve);
    }));
  }
  enqueue(t) {
    // if (this.resolvers.length) this.resolvers.shift()(t);
    // else this.promises.push(Promise.resolve(t));
    if (!this.resolvers.length) this._add();
    this.resolvers.shift()(t);
  }
  dequeue() {
    if (!this.promises.length) this._add();
    return this.promises.shift();
  }
  // now some utilities:
  isEmpty() { // there are no values available
    return !this.promises.length; // this.length <= 0
  }
  isBlocked() { // it's waiting for values
    return !!this.resolvers.length; // this.length < 0
  }
  get length() {
    return this.promises.length - this.resolvers.length;
  }
  [Symbol.asyncIterator]() {
    // Todo: Use AsyncIterator.from()
    return {
      next: () => this.dequeue().then(value => ({done: false, value})),
      [Symbol.asyncIterator]() { return this; },
    };
  }
}

I don't know TypeScript, but presumably it's simple to add the the necessary type annotations.

For better performance, use a Queue implementation with circular buffers instead of plain arrays, e.g. this one. You might also use only a single queue and remember whether you currently store promises or resolvers.

This is simply @Bergi's answer but with typescript + generics with some modifications to make it work with strict mode for my typescript peeps out there.

class AsyncBlockingQueue<T> {
  private _promises: Promise<T>[];
  private _resolvers: ((t: T) => void)[];

  constructor() {
    this._resolvers = [];
    this._promises = [];
  }

  private _add() {
    this._promises.push(new Promise(resolve => {
      this._resolvers.push(resolve);
    }));
  }

  enqueue(t: T) {
    if (!this._resolvers.length) this._add();
    const resolve = this._resolvers.shift()!;
    resolve(t);
  }

  dequeue() {
    if (!this._promises.length) this._add();
    const promise = this._promises.shift()!;
    return promise;
  }

  isEmpty() {
    return !this._promises.length;
  }

  isBlocked() {
    return !!this._resolvers.length;
  }

  get length() {
    return this._promises.length - this._resolvers.length;
  }
}