How to insert logo in the center of qrcode in Python?

If you use a high-redundancy algorithm (eg H), you can damage the generated QRCode up to a certain percentage. H means you can cover 30% of the data and it'll still work.

That means it's just a case of placing your image over the code. The format is up to you.

import pyqrcode
from PIL import Image
url = pyqrcode.QRCode('http://www.eqxiu.com',error = 'H')
url.png('test.png',scale=10)
im = Image.open('test.png')
im = im.convert("RGBA")
logo = Image.open('logo.png')
box = (135,135,235,235)
im.crop(box)
region = logo
region = region.resize((box[2] - box[0], box[3] - box[1]))
im.paste(region,box)
im.show()

Though this question is more than 1 year old now, but still I am posting my solution as I got it working hoping that it might help someone else.

CAUTION I generated the qr code image in png format. To get it working, pypng module must be installed.

import pyqrcode
from PIL import Image

# Generate the qr code and save as png
qrobj = pyqrcode.create('https://stackoverflow.com')
with open('test.png', 'wb') as f:
    qrobj.png(f, scale=10)

# Now open that png image to put the logo
img = Image.open('test.png')
width, height = img.size

# How big the logo we want to put in the qr code png
logo_size = 50

# Open the logo image
logo = Image.open('stackoverflow-logo.jpg')

# Calculate xmin, ymin, xmax, ymax to put the logo
xmin = ymin = int((width / 2) - (logo_size / 2))
xmax = ymax = int((width / 2) + (logo_size / 2))

# resize the logo as calculated
logo = logo.resize((xmax - xmin, ymax - ymin))

# put the logo in the qr code
img.paste(logo, (xmin, ymin, xmax, ymax))

img.show()