How to know if two arrays have the same values

Sort the arrays and compare their values one by one.

function arrayCompare(_arr1, _arr2) {
    if (
      !Array.isArray(_arr1)
      || !Array.isArray(_arr2)
      || _arr1.length !== _arr2.length
      ) {
        return false;
      }
    
    // .concat() to not mutate arguments
    const arr1 = _arr1.concat().sort();
    const arr2 = _arr2.concat().sort();
    
    for (let i = 0; i < arr1.length; i++) {
        if (arr1[i] !== arr2[i]) {
            return false;
         }
    }
    
    return true;
}

If your array items are not objects- if they are numbers or strings, for example, you can compare their joined strings to see if they have the same members in any order-

var array1= [10, 6, 19, 16, 14, 15, 2, 9, 5, 3, 4, 13, 8, 7, 1, 12, 18, 11, 20, 17];
var array2= [12, 18, 20, 11, 19, 14, 6, 7, 8, 16, 9, 3, 1, 13, 5, 4, 15, 10, 2, 17];

if(array1.sort().join(',')=== array2.sort().join(',')){
    alert('same members');
}
else alert('not a match');

If you want to check only if two arrays have same values (regardless the number of occurrences and order of each value) you could do this by using lodash:

_.isEmpty(_.xor(array1, array2))

Short, simple and pretty!