How to log source file name and line number in Python
On top of Seb's very useful answer, here is a handy code snippet that demonstrates the logger usage with a reasonable format:
#!/usr/bin/env python
import logging
logging.basicConfig(format='%(asctime)s,%(msecs)d %(levelname)-8s [%(filename)s:%(lineno)d] %(message)s',
datefmt='%Y-%m-%d:%H:%M:%S',
level=logging.DEBUG)
logger = logging.getLogger(__name__)
logger.debug("This is a debug log")
logger.info("This is an info log")
logger.critical("This is critical")
logger.error("An error occurred")
Generates this output:
2017-06-06:17:07:02,158 DEBUG [log.py:11] This is a debug log
2017-06-06:17:07:02,158 INFO [log.py:12] This is an info log
2017-06-06:17:07:02,158 CRITICAL [log.py:13] This is critical
2017-06-06:17:07:02,158 ERROR [log.py:14] An error occurred
Sure, check formatters in logging docs. Specifically the lineno and pathname variables.
%(pathname)s Full pathname of the source file where the logging call was issued(if available).
%(filename)s Filename portion of pathname.
%(module)s Module (name portion of filename).
%(funcName)s Name of function containing the logging call.
%(lineno)d Source line number where the logging call was issued (if available).
Looks something like this:
formatter = logging.Formatter('[%(asctime)s] p%(process)s {%(pathname)s:%(lineno)d} %(levelname)s - %(message)s','%m-%d %H:%M:%S')