How to map multiple lists to one dictionary?

dict((z[0], list(z[1:])) for z in zip(list1, list2, list3))

will work. Or, if you prefer the slightly nicer dictionary comprehension syntax:

{z[0]: list(z[1:]) for z in zip(list1, list2, list3)}

This scales up to to an arbitrary number of lists easily:

list_of_lists = [list1, list2, list3, ...]
{z[0]: list(z[1:]) for z in zip(*list_of_lists)} 

And if you want to convert the type to make sure that the value lists contain all integers:

def to_int(iterable):
    return [int(x) for x in iterable]

{z[0]: to_int(z[1:]) for z in zip(*list_of_lists)}

Of course, you could do that in one line, but I'd rather not.

In [12]: list1 = ('a','b','c')

In [13]: list2 = ('1','2','3')

In [14]: list3 = ('4','5','6')

In [15]: zip(list2, list3)
Out[15]: [('1', '4'), ('2', '5'), ('3', '6')]

In [16]: dict(zip(list1, zip(list2, list3)))
Out[16]: {'a': ('1', '4'), 'b': ('2', '5'), 'c': ('3', '6')}

In [17]: dict(zip(list1, zip(map(int, list2), map(int, list3))))
Out[17]: {'a': (1, 4), 'b': (2, 5), 'c': (3, 6)}

In [18]: dict(zip(list1, map(list, zip(map(int, list2), map(int, list3)))))
Out[18]: {'a': [1, 4], 'b': [2, 5], 'c': [3, 6]}

For an arbitrary number of lists, you could do this:

dict(zip(list1, zip(*(map(int, lst) for lst in (list2, list3, list4, ...)))))

Or, to make the values lists rather than tuples,

dict(zip(list1, map(list, zip(*(map(int, lst) for lst in (list2, list3, list4, ...))))))