How to match any non white space character except a particular one?
You can use a character class:
/[^\s\\]/
matches anything that is not a whitespace character nor a \
. Here's another example:
[abc]
means "match a
, b
or c
"; [^abc]
means "match any character except a
, b
or c
".
You can use a lookahead:
/(?=\S)[^\\]/
On my system: CentOS 5
I can use \s
outside of collections but have to use [:space:]
inside of collections. In fact I can use [:space:]
only inside collections. So to match a single space using this I have to use [[:space:]]
Which is really strange.
echo a b cX | sed -r "s/(a\sb[[:space:]]c[^[:space:]])/Result: \1/"
Result: a b cX
- first space I match with
\s
- second space I match alternatively with
[[:space:]]
- the X I match with "all but no space"
[^[:space:]]
These two will not work:
a[:space:]b instead use a\sb or a[[:space:]]b
a[^\s]b instead use a[^[:space:]]b
This worked for me using sed [Edit: comment below points out sed doesn't support \s]
[^ ]
while
[^\s]
didn't
# Delete everything except space and 'g'
echo "ghai ghai" | sed "s/[^\sg]//g"
gg
echo "ghai ghai" | sed "s/[^ g]//g"
g g