how to open and operate calculator with python code example
Example 1: how to make a python calculator
import time
def add():
n1 = input('Enter a number: ')
n2 = input('Enter another number: ')
time.sleep(1)
print(int(n1)+int(n2))
def multiply():
n1 = input('Enter a number: ')
n2 = input('Enter another number: ')
time.sleep(1)
print(int(n1)*int(n2))
def divide():
n1 = input('Enter a number: ')
n2 = input('Enter another number: ')
time.sleep(1)
print(int(n1)int(n2))
def subtract():
n1 = input('Enter a number: ')
n2 = input('Enter another number: ')
time.sleep(1)
print(int(n1)-int(n2))
run = True
while run:
ans = input('Select an opreation: ')
if(ans=='Addition'):
add()
if(ans=='Divide'):
divide()
if(ans=='Multiply'):
multiply()
if(ans=='Subtract'):
subtract()
Example 2: how to create calculator in python
def add(x, y):
return x + y
def subtract(x, y):
return x - y
def multiply(x, y):
return x * y
def divide(x, y):
return x / y
print("Select operation.")
print("1.Add")
print("2.Subtract")
print("3.Multiply")
print("4.Divide")
while True:
choice = input("Enter choice(1/2/3/4): ")
if choice in ('1', '2', '3', '4'):
num1 = float(input("Enter first number: "))
num2 = float(input("Enter second number: "))
if choice == '1':
print(num1, "+", num2, "=", add(num1, num2))
elif choice == '2':
print(num1, "-", num2, "=", subtract(num1, num2))
elif choice == '3':
print(num1, "*", num2, "=", multiply(num1, num2))
elif choice == '4':
print(num1, "/", num2, "=", divide(num1, num2))
break
else:
print("Invalid Input")