How to place the output jar into another folder with maven?
Another way would be maven-resources-plugin (find the current version here):
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-resources-plugin</artifactId>
<version>3.0.2</version>
<executions>
<execution>
<id>copy-files-on-build</id>
<phase>package</phase>
<goals>
<goal>copy-resources</goal>
</goals>
<configuration>
<outputDirectory>${basedir}/[TO-DIR]</outputDirectory>
<resources>
<resource>
<directory>[FROM-DIR]</directory>
<!--<include>*.[MIME-TYPE]</include>-->
<filtering>false</filtering>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>
You can use the outputDirectory parameter of the maven-jar-plugin for this purpose:
<project>
...
<build>
<plugins>
...
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-jar-plugin</artifactId>
<version>2.3.1</version>
<configuration>
<outputDirectory>../libs</outputDirectory>
</configuration>
</plugin>
...
</plugins>
</build>
...
</project>
But as cdegroot wrote, you should probably better not fight the maven way.
If you want to copy the artifact into a directory outside your project, solutions might be:
maven-jar-plugin
and configureoutputDirectory
maven-antrun-plugin
and copy taskcopy-maven-plugin
by Evgeny Goldin
Example for the copy-maven-plugin
is:
<plugin>
<groupId>com.github.goldin</groupId>
<artifactId>copy-maven-plugin</artifactId>
<version>0.2.5</version>
<executions>
<execution>
<id>deploy-to-local-directory</id>
<phase>install</phase>
<goals>
<goal>copy</goal>
</goals>
<configuration>
<skipIdentical>false</skipIdentical>
<failIfNotFound>false</failIfNotFound>
<resources>
<resource>
<description>Copy artifact to another directory</description>
<targetPath>/your/local/path</targetPath>
<directory>${project.build.directory}</directory>
<includes>
<include>*.jar</include>
</includes>
</resource>
</resources>
</configuration>
</execution>
</executions>
</plugin>