How to read user input until EOF?
Use file.read
:
input_str = sys.stdin.read()
According to the documentation:
file.read([size])
Read at most size bytes from the file (less if the read hits EOF before obtaining size bytes). If the size argument is negative or omitted, read all data until EOF is reached.
>>> import sys
>>> isinstance(sys.stdin, file)
True
BTW, dont' use input
as a variable name. It shadows builtin function input
.
In Python 3 you can iterate over the lines of standard input, the loop will stop when EOF is reached:
from sys import stdin
for line in stdin:
print(line, end='')
line
includes the trailing \n
character
Run this example online: https://ideone.com/rUXCIe
This might be what most people are looking for, however if you want to just read the whole input until EOF into a single variable (like OP), then you might want to look at this other answer.
You could also do the following:
acc = []
out = ''
while True:
try:
acc.append(raw_input('> ')) # Or whatever prompt you prefer to use.
except EOFError:
out = '\n'.join(acc)
break
With sys.stdin.readline()
you could write like this:
import sys
while True:
input_ = sys.stdin.readline()
if input_ == '':
break
print type(input_)
sys.stdout.write(input_)
Remember, whatever your input is, it is a string.
For raw_input
or input
version, write like this:
while True:
try:
input_ = input("Enter:\t")
#or
_input = raw_input("Enter:\t")
except EOFError:
break
print type(input_)
print type(_input)
print input_
print _input