How to remove space from string?

Since you're using bash, the fastest way would be:

shopt -s extglob # Allow extended globbing
var=" lakdjsf   lkadsjf "
echo "${var//+([[:space:]])/}"

It's fastest because it uses built-in functions instead of firing up extra processes.

However, if you want to do it in a POSIX-compliant way, use sed:

var=" lakdjsf   lkadsjf "
echo "$var" | sed 's/[[:space:]]//g'

The tools sed or tr will do this for you by swapping the whitespace for nothing

sed 's/ //g'

tr -d ' '

Example:

$ echo "   3918912k " | sed 's/ //g'
3918912k

Try doing this in a shell:

var="  3918912k"
echo ${var//[[:blank:]]/}

That uses parameter expansion (it's a non posix feature)

[[:blank:]] is a POSIX regex class (remove spaces, tabs...), see http://www.regular-expressions.info/posixbrackets.html

Related