How to run mysql command on bash?
I have written a shell script which will read data from properties file and then run mysql script on shell script. sharing this may help to others.
#!/bin/bash
PROPERTY_FILE=filename.properties
function getProperty {
PROP_KEY=$1
PROP_VALUE=`cat $PROPERTY_FILE | grep "$PROP_KEY" | cut -d'=' -f2`
echo $PROP_VALUE
}
echo "# Reading property from $PROPERTY_FILE"
DB_USER=$(getProperty "db.username")
DB_PASS=$(getProperty "db.password")
ROOT_LOC=$(getProperty "root.location")
echo $DB_USER
echo $DB_PASS
echo $ROOT_LOC
echo "Writing on DB ... "
mysql -u$DB_USER -p$DB_PASS dbname<<EOFMYSQL
update tablename set tablename.value_ = "$ROOT_LOC" where tablename.name_="Root directory location";
EOFMYSQL
echo "Writing root location($ROOT_LOC) is done ... "
counter=`mysql -u${DB_USER} -p${DB_PASS} dbname -e "select count(*) from tablename where tablename.name_='Root directory location' and tablename.value_ = '$ROOT_LOC';" | grep -v "count"`;
if [ "$counter" = "1" ]
then
echo "ROOT location updated"
fi
This one worked, double quotes when $user and $password are outside single quotes. Single quotes when inside a single quote statement.
mysql --user="$user" --password="$password" --database="$user" --execute='DROP DATABASE '$user'; CREATE DATABASE '$user';'
Use double quotes while using BASH variables.
mysql --user="$user" --password="$password" --database="$database" --execute="DROP DATABASE $user; CREATE DATABASE $database;"
BASH doesn't expand variables in single quotes.