How to solve for viewpager : The specified child already has a parent. You must call removeView() on the child's parent first
I had the same problem when I used
View res = inflater.inflate(R.layout.fragment_guide_search, container);
inside Fragment.onCreateView(...
You must call
View res = inflater.inflate(R.layout.fragment_guide_search, container, false);
or
View res = inflater.inflate(R.layout.fragment_guide_search, null);
I have also faced this problem.
You can solve it by just add single line mViewPager.setOffscreenPageLimit(3);
public class SwipeyTabsSampleActivity extends FragmentActivity {
...
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mViewPager = (ViewPager) findViewById(R.id.viewpager);
mTabs = (SwipeyTabs) findViewById(R.id.swipeytabs);
SwipeyTabsPagerAdapter adapter = new SwipeyTabsPagerAdapter(this,
getSupportFragmentManager());
mViewPager.setAdapter(adapter);
mViewPager.setOffscreenPageLimit(3); <------ Add this one
}
}
Good Luck.
First, the answer by RB Patel to insert code (shown below), worked like a charm, but as I read about this feature, I realized it was intended as a potential optimization and isn't actually the solution to the bug.
mViewPager.setOffscreenPageLimit(3);
The Android Developer site says the following about this method:
setOffscreenPageLimit(int limit) - Set the number of pages that should be retained to either side of the current page in the view hierarchy in an idle state.
It seems like this just sets a limit on the number of pages cached to the right or left of the current page. In my case this was just a band aid for the problem, yes the error stopped and things worked smoothly, but I still had bad code lurking in my program which simply not being executed. I believe this method was intended to be used as an optimization and not an actual fix to the bug.
I ran into this problem when trying to overload the instantiateItem() method in a custom class which extends PagerAdapter. My error was thrown after I would navigate back to a tab/page which I had previously visited/instantiated.
I am new to Android but I'll do my best to explain my solution. The line which throw this error was the following:
v.addView(child);
If I understand this correctly, it was choking because the child was already instantiated previously and assigned a parent.
When I would navigate back to a previously visited view/page I was trying to add a view which already had a parent layout view to a new Layout, hence the error.
Solution: I just checked to see if the child view I was trying to display (instantiate) was already instantiated somewhere else by seeing if it had a parent view set. If the child view had already been created, then I just used the parent of the child view instead of creating a new Layout.
Here is my code (I apologize if it offends any experts):
@Override
public Object instantiateItem(View container, int position) {
LinearLayout v = new LinearLayout(mContext);
//the view being loaded (unless it already was then we have to handle it)
View child = mViews.get(position);
//If the child view was loaded already then it will have a parent view it belongs to
//We return the parent view instead of adding the child to the LinearLayout we just created and returning that new layout.
if(child.getParent() != null) {
View parent = (View) child.getParent();
((ViewPager) container).addView(parent);
return parent;
}
//first time instantiating a child view/page
v.addView(child);
// These lines execute the first time a given page is instantiated
((ViewPager) container).addView(v);
return v;
}