How to sort mongodb with pymongo

You can try this:

db.Account.find().sort("UserName")  
db.Account.find().sort("UserName",pymongo.ASCENDING)   
db.Account.find().sort("UserName",pymongo.DESCENDING)

Why python uses list of tuples instead dict?

In python, you cannot guarantee that the dictionary will be interpreted in the order you declared.

So, in mongo shell you could do .sort({'field1':1,'field2':1}) and the interpreter would sort field1 at first level and field 2 at second level.

If this syntax was used in python, there is a chance of sorting by field2 at first level. With tuple, there is no such risk.

.sort([("field1",pymongo.ASCENDING), ("field2",pymongo.DESCENDING)])

.sort(), in pymongo, takes key and direction as parameters.

So if you want to sort by, let's say, id then you should .sort("_id", 1)

For multiple fields:

.sort([("field1", pymongo.ASCENDING), ("field2", pymongo.DESCENDING)])

This also works:

db.Account.find().sort('UserName', -1)
db.Account.find().sort('UserName', 1)

I'm using this in my code, please comment if i'm doing something wrong here, thanks.

Related