How to split a path properly in PHP
Something like this maybe (if I got your intention right):
<?php
$str = 'dir1/dir2/dir3/dir4';
$output = array();
$chunks = explode('/', $str);
foreach ($chunks as $i => $chunk) {
$output[] = sprintf(
'<a href="#/%s">%s</a>',
implode('/', array_slice($chunks, 0, $i + 1)),
$chunk
);
}
echo implode(' >> ', $output);
Output:
<a href="#/dir1">dir1</a> >>
<a href="#/dir1/dir2">dir2</a> >>
<a href="#/dir1/dir2/dir3">dir3</a> >>
<a href="#/dir1/dir2/dir3/dir4">dir4</a>
I'd do it like this...
<?php
$path = 'dir1/dir2/dir3/dir4';
$dirs = explode('/', $path);
while (count($dirs) > 0) {
$link = '/' . implode($dirs, '/');
$text = array_pop($dirs);
$breadcrumb = "<a href=\"$link\">$text</a>" . $breadcrumb;
if (count($dirs) > 0) {
$breadcrumb = ' >> ' . $breadcrumb;
}
}
echo $breadcrumb;
If you are getting this path based on the URL you shouldn't need to use DIRECTORY_SEPARATOR
because URLs should always use /
. If it is derived from the filesystem path you would need to swap it in instead of '/'
on line 4.
Var 1
<?php
$str = '/dir1/dir2/dir3/dir4';
$arr = array_filter(explode('/',$str));
$out = array('/'.implode('/',$arr).'/');
while((array_pop($arr) and !empty($arr))){
$out[] = '/'.implode('/',$arr).'/';
};
print_r($out);
/*
Array(
[0] => /dir1/dir2/dir3/dir4/
[1] => /dir1/dir2/dir3/
[2] => /dir1/dir2/
[3] => /dir1/
)
*/
?>
Var 2 ( Links )
<?php
$str = '/dir1/dir2/dir3/dir4';
$arr = array_filter(explode('/',$str));
$out = array('<a href="/'.implode('/',$arr).'/">'.basename($str).'</a>');
while((array_pop($arr) and !empty($arr))){
$out[] = '<a href="/'.implode('/',$arr).'/">'.end($arr).'</a>';
};
print_r($out);
/*
Array
(
[0] => <a href="/dir1/dir2/dir3/dir4/">dir4</a>
[1] => <a href="/dir1/dir2/dir3/">dir3</a>
[2] => <a href="/dir1/dir2/">dir2</a>
[3] => <a href="/dir1/">dir1</a>
)
*/
?>