How to split string while ignoring portion in parentheses?
var regex = /,(?![^(]*\)) /;
var str = "bibendum, morbi, non, quam (nec, dui, luctus), rutrum, nulla";
var splitString = str.split(regex);
Here you go. An explanation of the regex:
, //Match a comma
(?! //Negative look-ahead. We want to match a comma NOT followed by...
[^(]* //Any number of characters NOT '(', zero or more times
/) //Followed by the ')' character
) //Close the lookahead.
You don't need fancy regular expressions for this.
s="bibendum, morbi, non, quam (nec, dui, luctus), rutrum, nulla"
var current='';
var parenthesis=0;
for(var i=0, l=s.length; i<l; i++){
if(s[i] == '('){
parenthesis++;
current=current+'(';
}else if(s[i]==')' && parenthesis > 0){
parenthesis--;
current=current+')';
}else if(s[i] ===',' && parenthesis == 0){
console.log(current);current=''
}else{
current=current+s[i];
}
}
if(current !== ''){
console.log(current);
}
Change console.log for an array concatenation or what ever you want.
Instead of focusing on what you do not want it's often easier to express as a regular expression what you want, and to match
that with a global regex:
var str = "bibendum, morbi, non, quam (nec, dui, luctus), rutrum, nulla";
str.match(/[^,]+(?:\(+*?\))?/g) // the simple one
str.match(/[^,\s]+(?:\s+\([^)]*\))?/g) // not matching whitespaces