How to stop a DispatchWorkItem in GCD?

GCD does not perform preemptive cancelations. So, to stop a work item that has already started, you have to test for cancelations yourself. In Swift, cancel the DispatchWorkItem. In Objective-C, call dispatch_block_cancel on the block you created with dispatch_block_create. You can then test to see if was canceled or not with isCancelled in Swift (known as dispatch_block_testcancel in Objective-C).

func testDispatchItems() {
    let queue = DispatchQueue.global()

    var item: DispatchWorkItem?

    // create work item

    item = DispatchWorkItem { [weak self] in
        for i in 0 ... 10_000_000 {
            if item?.isCancelled ?? true { break }
            print(i)
            self?.heavyWork()
        }
        item = nil    // resolve strong reference cycle of the `DispatchWorkItem`
    }

    // start it

    queue.async(execute: item!)

    // after five seconds, stop it if it hasn't already

    queue.asyncAfter(deadline: .now() + 5) {
        item?.cancel()
        item = nil
    }
}

Or, in Objective-C:

- (void)testDispatchItem {
    dispatch_queue_t queue = dispatch_get_global_queue(QOS_CLASS_DEFAULT, 0);

    static dispatch_block_t block = nil;  // either static or property

    __weak typeof(self) weakSelf = self;

    block = dispatch_block_create(0, ^{
        for (long i = 0; i < 10000000; i++) {
            if (dispatch_block_testcancel(block)) { break; }
            NSLog(@"%ld", i);
            [weakSelf heavyWork];
        }

        block = nil;
    });

    // start it

    dispatch_async(queue, block);

    // after five seconds, stop it if it hasn't already

    dispatch_after(dispatch_time(DISPATCH_TIME_NOW, (int64_t)(5 * NSEC_PER_SEC)), dispatch_get_main_queue(), ^{
        if (block) { dispatch_block_cancel(block); }
    });
}