How to tell if terminal session is running within screen
Typically, $STY
will be set.
So:
if [ -n "$STY" ]; then
echo "I'm most likely running under screen"
fi
$STY
is typically what you need to talk to your screen
. That is used to construct the path of the Unix domain socket used to control screen
(something like /var/run/screen/S-$USER/$STY
.
Now, that won't work for instance if from that screen, you ssh
to another machine. The shell started there won't have $STY
in its environment, and that wouldn't be of any use to it anyway, since it wouldn't be able to access the Unix domain sockets on your machine.
However, it is possible to query the terminal with an escape sequence to determine its type:
if [ -t 1 ] && [ -t 0 ]; then
s=$(stty -g)
stty -icanon -echo min 0 time 3
printf '\033[>c'
type=$(dd count=1 2> /dev/null)
stty "$s"
case $type in
(*'>83;'*) echo "this is screen"
esac
fi
Another approach, as suggested by @val0x00ff is to check the value of the $TERM
environment variable. That value is meant to tell applications what type of terminal they're talking to. It is set by screen
to something that starts with screen
(as screen
can implement different variants of terminals). $TERM
is passed accross rlogin
, rsh
, telnet
, ssh
. It's not as guaranteed to work as the above but is simpler and less intrusive.
case $TERM in
(screen*) echo "I'm more than likely running in screen"
esac
Like for the previous solution, you may be running in screen
, but you may not be able to issue commands to it with screen -X
for instance. However note, that you can pass commands using escape sequences (though it's not enabled by default for security reasons).
When running in screen your $TERM
environment variable changes to screen. You can check in the script e.g
if [[ "$TERM" == screen* ]]; then
echo "Running in screen"
else
echo "Outside screen"
fi
That would be one of the approaches. echo $TERM
outside the screen and again echo $TERM
inside the screen and see the difference