How to trim a string after a specific character in java

You can use:

result = result.split("\n")[0];

Assuming you just want everything before \n (or any other literal string/char), you should use indexOf() with substring():

result = result.substring(0, result.indexOf('\n'));

If you want to extract the portion before a certain regular expression, you can use split():

result = result.split(regex, 2)[0];

---

String result = "34.1 -118.33\n<!--ABCDEFG-->";

System.out.println(result.substring(0, result.indexOf('\n')));
System.out.println(result.split("\n", 2)[0]);

34.1 -118.33
34.1 -118.33

(Obviously \n isn't a meaningful regular expression, I just used it to demonstrate that the second approach also works.)