How to use automatic CSS hyphens with `word-break: break-all`?
Hyphens are inserted if the browser supports & language includes a hyphenation dictionary. But your
aaaaaaaaaaaaaaaaaa
isn't in a dictionary.
Therefore you have to insert soft hyphens ­
to your satisfaction like in https://jsfiddle.net/LJYj3/5/
Here's more food for thought: https://stackoverflow.com/a/856322/1696030
The -ms-hyphens
property only works in IE10+. It's not possible in IE9 or below.
See the browser compatibility chart at the bottom of the reference link you provided.
It doesn't work in Chrome yet: WebKit Hyphenation
The word-break
property and hyphenation are two completely different things. The first one, originally intended for East Asian languages mainly, does bad things to languages like English: it arbitr arily cuts w ords at some poi nts without ind icating that a word has been broke n.
So you should decide whether you have an expression where a line break can be inserted by a browser at any point or whether you want hyphenation.
For hyphenation, the CSS code as such is OK, though many people would advice putting the standard property setting hyphens: auto
last, after prefixed properties. But it requires that the language of the text be declared in HTML markup, using e.g. <div lang=en>
. Moreover, browser support is still limited: IE 9 does not support such hyphenation, and the support in IE 10 covers a relatively small set of languages (including English of course).
For automatic hyphenation on IE 9, you would need to use either server-side programmed hyphenation or, simpler, client-side hyphenation with tools like Hyphenator.js.
I was not able to find any css solution for this, so fix it with js.
const addWordBreaks = (str, maxLength = 10) => {
const words = str.split(" ");
const newWords = [];
words.forEach(function(word) {
if (word.length > maxLength) {
const firstWord = word.substr(0,maxLength);
const endWord = word.substr(maxLength, word.length-1);
newWords.push(firstWord +"- \n");
newWords.push(endWord)
} else {
newWords.push(word)
}
});
return newWords.join(" ");
}