How to use both default and custom copy constructor in C++?

The simplest approach to this would be to wrap up the pointers into classes that will perform the 'repair' manually in their copy constructor, then you can happily use the default copy constructor.

Wrap the things you don't want to change in a struct, and derive (privately) from it. In your copy constructor, simply invoke the copy constructor of your base class.

No you cannot have both default and your own copy c-tor.

But there are two workarounds with this problem:

---

1 Enclose your pointers in some class with defined copy semantics

Example:

class A {
public:
private:
   int trivial1;
   int trivial2;
   ...
   SomePointer  nontrivialMember;
};

class SomePointer {
public:
  SomePointer(const SomePointer&); // here the non trivial part of A copy semantics
  int* nonTrivialMember;
};

---

2 Enclose the trivial parameters in some trivial structure

Example:

class A {
public:
   A(const A& o) : data(o.data) {
     // non trivial part
   }
private:
   struct Data {
     int trivial1;
     int trivial2;
     ...
   } data;
   int* nontrivialMember;
};

---

I would always select the first solution.

[UPDATE]

There is also 3rd solution, very similar to my second, enclose your trivial part in privately inherited base class. I'd still prefer the 1st solution.